gabotron
New Member
Hi,
I have been searching this sub-forum for a resolution to my problem but it seems that I can't find a specific one. Basically, my problem is that every time I create a shortcut, usually by right-clicking on an executable and then choosing Create Shortcut from the context menu, the default path is always set to, for example, C:\Program Files (x86)\My Application\myapplication.exe. However, I already set my default Program Files and Program Files (x86) location to be in the D:\ drive.
Nature of the Problem
After installing Vista Ultimate x64, I installed TuneUp Utilities 2009 and from there, I set the default Program Files location to my second partition which is D:\. I expected TuneUp Utilities to make the necessary changes to the registry. To make sure that no programs were left out in C:\Program Files and C:\Program Files (x86), I manually re-created the 2 folders in D:\ and then copied all the files and folders inside. I rebooted afterwards.
Upon boot, my expectations toward TuneUp Utilities 2009 seemed to be correct because the default now points to D:\ (whenever I install 64-bit or 32-bit programs). I had no problems running the applications as well.
The Problem
But a problem arises whenever a shortcut is made. It doesn't matter whether it was created by the installer itself or created manually. The target path always points to C:\ while the Start In path points to the correct one, which is D:\. Whether it be in the Start Menu, on the Desktop, or in the Quick Launch menu, the same behavior happens.
It's often a pain to edit the shortcuts manually- doing a right-click > Properties > change C to D > Change Icon > Apply > OK every time I install a new application or decide to create a shortcut for a certain portable app. I believe there's a registry entry that I can change so that the default Shortcut path now defaults to D:\ instead of C:\. Could you point me in that direction?
Please take a look at the sample image I posted below:
TIA
I have been searching this sub-forum for a resolution to my problem but it seems that I can't find a specific one. Basically, my problem is that every time I create a shortcut, usually by right-clicking on an executable and then choosing Create Shortcut from the context menu, the default path is always set to, for example, C:\Program Files (x86)\My Application\myapplication.exe. However, I already set my default Program Files and Program Files (x86) location to be in the D:\ drive.
Nature of the Problem
After installing Vista Ultimate x64, I installed TuneUp Utilities 2009 and from there, I set the default Program Files location to my second partition which is D:\. I expected TuneUp Utilities to make the necessary changes to the registry. To make sure that no programs were left out in C:\Program Files and C:\Program Files (x86), I manually re-created the 2 folders in D:\ and then copied all the files and folders inside. I rebooted afterwards.
Upon boot, my expectations toward TuneUp Utilities 2009 seemed to be correct because the default now points to D:\ (whenever I install 64-bit or 32-bit programs). I had no problems running the applications as well.
The Problem
But a problem arises whenever a shortcut is made. It doesn't matter whether it was created by the installer itself or created manually. The target path always points to C:\ while the Start In path points to the correct one, which is D:\. Whether it be in the Start Menu, on the Desktop, or in the Quick Launch menu, the same behavior happens.
It's often a pain to edit the shortcuts manually- doing a right-click > Properties > change C to D > Change Icon > Apply > OK every time I install a new application or decide to create a shortcut for a certain portable app. I believe there's a registry entry that I can change so that the default Shortcut path now defaults to D:\ instead of C:\. Could you point me in that direction?
Please take a look at the sample image I posted below:

TIA
My Computer
System One
-
- CPU
- Intel Core 2 Quad Q8200 @ 2.33 GHz stock
- Motherboard
- MSI P45 Platinum Zilent
- Memory
- 2 x 2GB Team Elite DDR2-800
- Graphics card(s)
- 1 x Palit Radeon HD4870 Sonic Dual Edition 512MB 256bit
- Monitor(s) Displays
- HP w2228h
- Screen Resolution
- 1680 x 1050
- Hard Drives
- 1 x 640GB Seagate Barracuda SATA 32mb cache 1 x 200GB Seagate Barracuda PATA 8mb cache
- PSU
- Corsair HX620
- Cooling
- Zalman CNPS 9700LED
- Mouse
- A4Tech X-750BF
- Keyboard
- A4Tech X7 G800
- Internet Speed
- 768kbps